AB is a diameter of a circle and C is any point on the circumference of the circle. Then the area of ` A B C` is maximum when it is isosceles the area of ` A B C` is minimum when it is isosceles the perimeter of ` A B C` is minimum when it is isosceles

Explanation

`angle {ACB}=90^{circ}`



By Pythagoras theorem



`x^{2}+y^{2}=4 a^{2} `


`y=sqrt{4 a^{2}-x^{2}}`



Area will be maximum


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