(1-i)^3/(1-i^3) = -2...

`(1-i)^3/(1-i^3) = -2`

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If frac{(1+i)^3}{(1-i)^3}-frac{(1-i)^3}{(1+i)^3} = x+iy , then

(1-i)(1+2i)(1-3i)=

The value of 1+(1+i)+(1+i^2) +(1+i^3) =

Reduce ((1)/(1+2i)+(3)/(1-i))((3-2i)/(1+3i)) to the form (a + ib).

Reduce to the form A + IB ((1-i)^2-(1+i)^2)/((1-i)^3+(1+i)^3)

Let z_1=((1+sqrt(3)i)^2(sqrt(3)-i))/(1-i) and z_2=((sqrt(3)+i)^2(1-sqrt(3)i))/(1+i) then

((1+i)^(2))/(3-i)

(2/(1-i) + 3/(1+i))((2+3i)/(4+5i)) is equal to

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