Find the area bounded by the curves `y=2x-x^2` and the straight line `y=-xdot`

Explanation

Area `=int_{0}^{3} 2 x-x^{2}+x d x`


`=int_{0}^{3} 3 x-x^{2} d x=[frac{3 x^{2}}{2}-frac{x^{3}}{3}]_{0}^{3}`


`=(frac{3.9}{2}-frac{27}{3})-0`


`=frac{27}{3}-frac{27}{3}`


`=27(frac{3-2}{6})`


`=frac{27}{6}`