Determine the area under the curve `y=sqrt(a^2-x^2)` included between the lines `x=0a n dx=adot`

Explanation

Given curve `y=sqrt(a^2-x^2)`
`=>y^2=a^2-x^2)`
`=>x^2+y^2=a^2`
Required area `=int_0^a(y dx)`
`= int_0^a(sqrt(a^2-x^2))dx`
`[x/2 sqrt(a^2-x^2)+a^2/2sin^-1x/a]_0^a`
`[a/2 sqrt(a^2-a^2)+a^2/2sin^-1a/a]-[0/2 sqrt(a^2-0^2)+a^2/2sin^-1(0)/a]`
`=a^2/2xxpi/2`
`=(pia^2)/4 `sq.units