" The equation of the tangent to the curve "y=be^(x/o)" at the point where it crosses the "y" -axis,is "

The equation to the tangent to the curve y = be ^(-x/a) at the point where it crosses the y-axis is

The equation of the tangent to the curve y= be^(-(x)/(a)) at the point where it crosses the y-axis is-

The equation of the tangent to the curve y=be^(-x/a) at the point where it crosses the y-axis is a)(x)/(a)-(y)/(b)=1( b) ax+by=1 c)ax -by=1( d) (x)/(a)+(y)/(b)=1

The equation to the tangent to the curve y=be^(x//a) at the point where x=0 is

The equation of tangent to the curve y=be^(-x//a) at the point where it crosses Y-axis is

The equation of tangent to the curve y=b^(-x//a) at the point where it crosses Y-axis is

Write the equation of the tangent to the curve y=x^2-x+2 at the point where it crosses the y-axis.

Write the equation of the tangent to the curve y=x^2-x+2 at the point where it crosses the y-axis.