(1-tan2^(@)cot62^(@))/(tan152^(@)-cot88^(@))=

(1-tan2^(0)cot62^(@))/(tan152^(0)-cot88^(@))(a)sqrt3(b)-sqrt3(c)sqrt2-1(d)1-sqrt2^(@)

(1- tan 2 ^(@) cot 62^(@))/(tan 152^(@) -cot 88^(@))=

(1- tan 2 ^(@) cot 62^(@))/(tan 152^(@) -cot 88^(@))=

If (1- tan2^(@) cot 62^(@))/( tan 152^(@) - cot88^(@))=ksqrt(3) , then value of k is

Find the value of (cot25^(@)+cot55^(@))/(tan25^(@)+tan55^(@))+(cot55^(@)+cot100^(@))/(tan55^(@)+tan100^(@))+(cot100^(@)+cot25^(@))/(tan100^(@)+tan25^(@))

cot12^(@)*cot 24^(@)*cot28^(@)*cot32^(@)*cot48^(@)*cot88^(@)=…….. i) tan45 ii) 2tan15.tan45.tan75 iii) 2tan15.tan45.tan75 iv) tan15.tan45.tan75

Find the value of (cot 25^(@)+cot 55^(@))/(tan 25^(@)+tan55^(@))+(cot 55^(@)+cot 100^(@))/(tan 55^(@)+tan 100^(@))+(cot 100^(@)+cot 25^(@))/(tan 100^(@)+tan 25^(@))

If (1-tan2cot62)/(tan152-cot88)=k sqrt(3) then k=

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2

Without using trigonometric tables , prove that : (i) tan20^(@)tan40^(@) tan45^(@)tan50^(@)tan70^(@)=1 (ii) tan1^(@) tan2^(@)tan60^(@)tan88^(@)tan89^(@)=sqrt(3) (iii) cot5^(@)cot10^(@)cot30^(@)cot80^(@)cot85^(@)=sqrt(3) (iv) 4sin10^(@)sin20^(@)sin30^(@)sec70^(@)sec80^(@)=2