The area(in sq. units) of the smaller portionenclosed between the curves, `x^2+y^2=4 and y^2=3x,` is

Using method of integration, find the area (in sq. units) of the smaller portion enclosed between the curves, x^2 + y^2 = 4 and y^2 = 3x.

The area (in sq unit) of the region enclosed by the curves y = x^(2) and y = x^(3) is

The area (in sq. units) enclosed between the curves y=x^(2) " and " y=abs(x) is

The area (in sq. units) enclosed between the curves y=x^(2) " and " y=abs(x) is

The area (in sq. units) of the region bounded by the curves y=2-x^(2) and y=|x| is k, then the value of 3k is

The area (in sq. units) of the region bounded by the curves y=2-x^(2) and y=|x| is k, then the value of 3k is

Show that the area enclosed between the curves y = x and y=x^(3) is (1)/(2) sq unit.

The area (in sq units) of the region bounded by the curve y=sqrt(x) and the lines y=0,y=x-2, is