" 15."6x+5y rArr x+3y+1=2(x+6y-1)

6x + 5y = 7x + 3y + 1 = 2 ( x + 6y - 1 )

If (3x -4y) : (2x -3y) = (5x -6y) : (4x -5y) , find : x : y .

2x+3y=5 6x+9y=10

x+5y=15;2x-3y=1

Simplify (2x + y) (1 + 4x + 3y) -6x (x + y)

Solve for x and y : (1)/( 7x ) + ( 1) /( 6y) = 3, (1)/( 2x) - (1)/( 3y ) = 5 (x ne 0, y ne 0)

Use matrix methocd to solve the following system of equations: {:(6x - 9y - 20 z = -4), (4x - 15 y + 10z = -1),(2x - 3y - 5z = -1):}

Show that the lines 2x + 5y = 1, x - 3y = 6 and x + 5y + 2 = 0 are concurrent.

Find the equation of a circle, the co-ordinates of the ends of whose diameter are (-1,-3) and (2,5) Now the equation of circle (x-x_(1))(x-x_(2))+(y-y_(1))(y-y_(2))=0 rArr(x+1)(x-2)+(y+3)(y-5)=0 rArr x^(2)-x-2+ y^(2)-2y-15=0 rArr x^(2)+y^(2)-x-2y-17=0 We is the required equation.