" If "f(x)=(x-4)(x-5)(x-6)(x-7)" ,then "

Let f(x) =(x-4) (x-5) (x-6) (x-7) then :

Let f(x)=(x-4)(x-5)(x-6)(x-7) then.(A) f'(x)=0 has four roots (B)Three roots of f'(x)=0 lie in (4,5)uu(5,6)uu(6,7) (C) The equation f'(x)=0 has only one real root (D) Three roots of f'(x)=0 lie in (3,4)uu(4,5)uu(5,6)

Let f(x) = ( x-4) (x -5) ( x- 6 ) ( x- 7 ) then

If f(x)=3^(x)+4^(x)+5^(x)-6^(x), then f(x)

If f(x)=(x+1)/((x-2)(x-5)) , then in [4, 6]

(x-4)/(x-5)+(x-6)/(x-7)=(10)/(3)

Solve for x: (x-4)/(x-5)+(x-6)/(x-7)=10/3; x!=5,7

Given f(x) is a cubic polynomial in x . If f(x) is divided by (x+3),(x+4),(x+5)and (x+6) , then it leaves the remainders 0, 0 , 4 and 6 respectively . Find the remainder when f(x) is divided by x+7 .

Find all the x-intercepts of f(x)=((x-3)^4(x-6)^4(x-4)(5x-8))/((2x-5)(x-3)(x-6)^2)

If f:RR -{(7)/(5)} rarr RR-{(3)/(5)} be defined as f(x)=(3x+4)/(5x-7) then find f(-1) .