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Calculate the area of the region bounded by the parabolas `y^2=6xa n dx^2=6ydot`

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The intersecting points of the given parabolas are obtained by solving these equations for x and y, which are `O(0,0)` and `B(6,6)`.
`y=sqrt(6x)`
`=>y=x^2/6`
Hence Area `OABC=int_0^6(sqrt(6x)-x^2/6)dx`
`=abs(2sqrt(6)x^(3/2)/3-(x^3)/18)_0^6`
`=2sqrt(6)6^(3/2)/3-(6^3)/18`
`=12` sq.units
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