Find the distance of the point `(21,0)` from the plane `2x+y+2z+5=0.`

Explanation

We know that the distance of the point `(x_1,x_2,x_3)`from the plane
`ax+by+cz+d=0` is given by
`(abs(ax_1+by_1+cz_1+d))/sqrt(a^2+b^2+c^2)`
So, required distance ,
`=abs(2xx2+1+2xx0+5)/sqrt(2^2+1^2+2^2)`
`=10/3`