sin((pi)/(2)+theta)*cos((3 pi)/(2)+theta)*tan((5 pi)/(2)+0)*cot((1 pi)/(2)+0)=1

sin ((pi) / (2) + theta) * cos ((3 pi) / (2) + theta) * tan ((5 pi) / (2) + theta) * cot ((7 pi) / (2) ) + theta)

If tan theta=(3)/(4) and theta is not in first quadrant sin(sin((pi)/(2)+theta)-cot(pi-theta))/(tan((3 pi)/(2)-theta)-cos((3 pi)/(2)+theta))=

If tan((pi)/(2) sin theta)=cot((pi)/(2)cos theta) then sin(theta +(pi)/(4))=

Prove that (sin(3pi-theta)cos(theta- pi/2)tan((3pi)/(2)-theta))/(cosec((13pi)/(2)+theta)sec(3pi+theta)cot(theta- pi/2))=cos^(4)theta

sin""((pi)/2+ theta ) * cos (pi- theta ) * cot ""((3pi)/(2)+ theta ) - sin""((pi)/2- theta ) * sin""((3pi)/2 - theta ) * cot ""((pi)/2 + theta ) =

I : If sin((pi)/(4)cot theta)=cos ((pi)/(4)tan theta) then theta = n pi+pi//4, n in Z II : If tan ((pi)/(2)sin theta)=cot((pi)/(2)cos theta) then sin (theta + (pi)/(4))= pm (1)/(sqrt(2))

(sin^(3)theta-cos^(3)theta)/(sin theta-cos theta)-(cos theta)/(sqrt(1+cot^(2)theta))-2tan theta cot theta=-1 if theta in(0,(pi)/(2))(b)theta in((pi)/(2),pi)theta in(pi,(3 pi)/(2))(d)theta in((3 pi)/(2),2 pi)

sqrt((1-sin theta)/(1+sin theta))={sec theta-tan theta, if -(pi)/(2)

x cot((pi)/(2)+theta)+tan((pi)/(2)+theta)sin theta+csc((pi)/(2)+theta)=0

If (3 pi)/(2)