|[0,x-a,x-b],[x+a,0,x-c],[x+b,x+c,0]|=0

Solve the following : [[0,x-a,x-b],[x+a,0,x-c],[x+b,x+c,0]] =0

If f(x)=|[0,x-a, x-b], [x+a,0,x-c], [x+b, x+c,0]|,t h e n (a) f(a)=0 (b) f(b)=0 (c) f(0)=0 (d) f(1)=0

If a ne b ne c , then one value of x which satisfies the equation. [(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0)] = 0 is given by :

If f (x) = |(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0)| then

If f(x)=|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}| , then "............"

If f(x)=|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}| , then

If f(x)|{:(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0):}| then show that f(0)=0

If a ,b ,c are different, then the value of |[0,x^2-a, x^3-b],[ x^2+a,0,x^2+c],[ x^4+b, x-c,0]| is a. c b. a c. b d. 0