Find the equation of the plane passing through the intersection of the planes `2x-3y+z-4=0a n dx-y+z+1=0` and perpendicular to the plane `x+2y-3z+6=0.`

Explanation

To find the equation of the plane that passes through the intersection of the given planes and is perpendicular to another plane, we can follow these steps:

### Step 1: Write the equations of the given planes
The equations of the two planes are:
1. \( P_1: 2x - 3y + z - 4 = 0 \)
2. \( P_2: x - y + z + 1 = 0 \)

### Step 2: Form the equation of the plane through the intersection of the two planes
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