A projectile is fired with kinetic energy 1 kj. If its range is maximum, what will be its kinetic energy at the highest point of its trajectory ?

Explanation

here `(1)/(2) mv^(2)=1|KJ=1000J, theta=45^(@)`
At the highest Point, K.E. `=(1)/(2) m(v cos theta)^(2)=(1)/(2)(mv^(2))/(2)=(1000)/(2)=500J`.