Prove that the maximum horizontal range is four times the maximum height attained by the projectile, when fired at an inclination so as to have maximum horizontal range.

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is

Find the ratio of maximum horizontal range and the maximum height attained by the projectile. i.e. for theta_(0) = 45^(@)

For which angle of projection the horizontal range is 5 times the maximum height attrained ?

Is the maximum height attained byprojectile is largest when its horizontal range is largest when its norizontal range is maximum ?

If R is the maximum horizontal range of a particle, then the greatest height attained by it is :

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

If R and H are the horizontal range and maximum height attained by a projectile , than its speed of prjection is

If R is the horizontal range for theta inclination and h is the maximum height reached by the projectile, Then maximum range is

Two balls are thrown with the same speed from a point O at the same time so that their horizontal ranges are same. If the difference of the maximum height attained by them is equal to half of the sum of the maximum heights, then the angles of projection for the balls are

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is