the angle between the vectors `(hati+hatj)` and `(hatj+hatk)` is

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `90^(@)`

Answer

C

Explanation

`cos theta =(vecA * vecB)/(|vecA||vecB|)`
`=((hati+hatj)*(hatj+hatk))/(sqrt(1+1)+sqrt(1+1))=(0+1+0)/(2)`
`cos theta = (1)/(2) cos 60^(@)`
`theta=60^(@)`