A projectile rises to a height of 10 m and then falls at a distance of 30 m away from the projection. Its vertical displacement is

Options

A. 0 m
B. 5 m
C. 6 m
D. 7 m

Explanation

To solve the problem, we need to determine the vertical displacement of the projectile that rises to a height of 10 m and then falls to a distance of 30 m away from the projection point.

### Step-by-Step Solution:

1. **Understanding Vertical Displacement**:
- Vertical displacement is defined as the difference in the vertical position of an object from its initial position to its final position.

2. **Initial Position**:
- The projectile is launched from the ground level, which we can consider as the initial vertical position (0 m).

3. **Maximum Height**:
- The projectile reaches a maximum height of 10 m during its flight. However, this is not the final position.

4. **Final Position**:
- After reaching the maximum height, the projectile falls back down. Since it is stated that it falls at a distance of 30 m away from the projection point, it lands back on the ground.

5. **Calculating Vertical Displacement**:
- The final vertical position of the projectile when it lands is also 0 m (ground level).
- Therefore, the vertical displacement can be calculated as:
\[ \text{Vertical Displacement} = \text{Final Position} - \text{Initial Position} = 0 \, \text{m} - 0 \, \text{m} = 0 \, \text{m} \]

6. **Conclusion**:
- The vertical displacement of the projectile is 0 m.

### Final Answer:
The vertical displacement is **0 m**.

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