Your local radio station relays news signal as `V(t)=(20+4sin500 pi t)*cos(2 pi times10^(5)t)`Volts.Find the modulation index of the signal.

A modulated signal is represented as x(1) = 6 sin 1250 t + sin 10^(8) t then the mudulating index is

A audio signal 20sin2pi(1500t) amplitude modulates 40sin2pi(10^(5))t . The depth of modulation is

A audio signal 15sin2pi(1500t) amplitude modulates 60sin2pi(10^(5))t . The depth of modulation is

The equation of an FM signal is e = 6 sin (10^(6) t + 4 sin 10^(3) t ) . Then, the modulating frequency is

An alternating voltage is represented by V=80 sin(100 pi t)cos(100 pi t) volt, What is the peak voltage?

An audio signal represented as 25 sin 2pi ( 2000 t) amplitude modulated by a carrier wave : 60 sin 2pi (100,000)t . The modulation index of the modulated signal is

In amplitude modulation, the message signal V_(m)(t)=10sin(2pixx10^(5)t) volts and Carrier signal V_(C )(t)=20sin(2pixx10^(7)t) volts The modulated signal now contains the message signal with lower side band and upper side band frequency, therefore the bandwidth of modulated signal is alpha KHz. The value of alpha is

The audio signal used to modulate 60 sin (2pixx10^(6)t) is 15 sin 300 pi t . The depth of modulation is

A carrier wave V_(c)(t)=160 sin (2 pi xx 10^(6) t) volts is made to vary between V_("max") =200 V and V_("min") =120 V by a message signal V_(m) (t)=A_(m) sin (2 pi xx 10^(3) t) volts. The peak voltage A_(m) of the modulating signal is_____.

The equation Y=0.02 sin (500 pi t) cos (4.5x) represents