Find the plane passing through `(4,-1,2)` and parallel to the lines `(x+2)/3=(y-2)/(-1)=(z+1)/2a n d(x-2)/1=(y-3)/2=(z-4)/3`

Explanation

Equation of plane is: -


`a(x-4)+b(y-1)+c(z-2)=0 \text {. }`


Now, since it is parallel to line


`\frac{x+2}{3}=\frac{y-2}{-1}=\frac{z+1}{2}`


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