Find the distance between the parallel planes, ` vec rdot((2 hat i-3 hat j+6 hat k))=5` and `vec rdot((6 hat i-9 hat j+18 hat k))+20=0.`

Explanation

`\text { Let } \vec{\gamma}=x \hat{i}+y \hat{j}+z \hat{k} \text {. }`


`\vec{\gamma}(2 \hat{i}-3 \hat{j}+6 \hat{k})=(x \hat{i}+y \hat{j}+z \hat{k})(2 \hat{i}-3 \hat{j}+6 \hat{k})`


`\Rightarrow 2 x-3 y+6 z-5=0 \div \text { (1) }`


`\vec{r}(6 \hat{i}-9 \hat{j}+18 \hat{k})+20=(x \hat{i}+y \hat{j}+2 \hat{k}) `


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