`sin^6A+cos^6A+3sin^2A cos^2A=\ ` `0` b. `1` c. `2` d. `3`

sin^6A+cos^6A+3sin^2A cos^2A=\ a. 0 b. 1 c. 2 d. 3

sin^(6)A+cos^(6)A+3sin^(2)A cos^(2)A=0 b.1c2d.3

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

cos^6A-sin^6A=cos2A(1-1/4sin^2 2A)

sin ^(6) a + cos ^(6) A - 1 is equal to A. -3 sin ^(2) A cos ^(2) A B. 1 - 3 sin A cos A C. 1 + 3 sin ^(2) A cos ^(2) A D. 0

Prove that 2 (sin ^ (6) A + cos ^ (6) A) -3 (sin ^ (4) A + cos ^ (4) A) + 1 = 0

2 sin A cos ^(3) A-2 sin ^(3) A cos A= ................. A) sin 4A B) 1/2 sin 4 A C) 1/4 sin 4A D) 1/8 sin 4A

int(sin^(6)x+cos^(6)x+3sin^(2)x cos^(2)x)dx is equal to