Area of the curve `y^2 = (7 - x)(5+x)` above x-axis & between the ordinates `x = -5 and x = 1` is

(i) Find the area bounded by x^(2)+y^(2)-2x=0 and y = sin'(pix)/(2) in the upper half of the circle. (ii) Find the area bounded by the curve y = 2x^(4)-x^(2) , x-axis and the two ordinates cooreponding to the the minima to the function. (iii) Find area of the curve y^(2) = (7-x)(5+x) above x-axis and between the ordinates x = - 5 and x = 1 .

The area bounded by the curve y=(x-1)(x-2)(x-3) and x -axis lying between the ordinates x = 0 and x = 4 is

The area bounded by the curve y=(x-1)(x-2)(x-3) and x -axis lying between the ordinates x=0 and x=4 is

Find the area under the curve y = x^(2) above x-axis between the lines x = 6 and x = 4.

The area bounded by the curve y=(x-1)(x-2)(x-3) and X-axis lying between ordinates x=0 and x=3 is

The area bounded by the curve y = x^(2) , x-axis and the ordinates: x = - 1 and x= 1 is given by

The area bounded by the curve y = x^(3) , x-axis and the ordinates: x = - 1 and x= 1 is given by

The area bounded by the curve y = x^(3) , x-axis and the ordinates: x = - 1 and x= 1 is given by

The area bounded by the curve y = x^(3) , x-axis and the ordinates: x = - 1 and x= 1 is given by