Find the distance between the parallel planes `2x-y+2z+3=0a n d4x-2y+4z+5=0.`

Explanation

To find the distance between the parallel planes given by the equations \(2x - y + 2z + 3 = 0\) and \(4x - 2y + 4z + 5 = 0\), we can follow these steps:

### Step 1: Verify that the planes are parallel
The normal vector of the first plane \(2x - y + 2z + 3 = 0\) is \(\mathbf{n_1} = (2, -1, 2)\).
The normal vector of the second plane \(4x - 2y + 4z + 5 = 0\) is \(\mathbf{n_2} = (4, -2, 4)\).

To check if the planes are parallel, we can see if the normal vectors are scalar multiples of each other.

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