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" 12"int((x+2)dx)/(2x^(2)+6x+5)...

" 12"int((x+2)dx)/(2x^(2)+6x+5)

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int (x^(2)dx)/(x^(2)+6x+12)

int(x+2)/(2x^(2)+6x+5)*dx

If int(x+2)/(2x^(2) + 6x + 5)dx = P int (4x + 6)/(2x^(2) + 6x + 5)dx + (1)/(2) int (dx)/(2x^(2) + 6x + 5) then the values of P is a)1/3 b)1/2 c)1/4 d)2

int(x^(2))/(x^(2)+6x+12)dx

int(x^(2))/(x^(2)+6x-12)dx

If int(x+2)/(2x^(2)+6x+5)dx =P int(4x+6)/(2x^(2)+6x+5)dx+(1)/(2) int (dx)/(2x^(2)+6x+5') Then the value of P is

int(x^(2))/((x^(2)+6x-3))dx

Integrate: int((5x^2-12)dx)/((x^2-6x+13)^2)