If the line drawn from `(4,-1,2)` meets a plane at right angles at the point `(-10 ,5,4),` find the equation of the plane.

Explanation

since line is passing through points `(4,-1,2` and `)(-10,5,4)`

so `E q^{n}` of the given line is


`frac{x-4}{-10-4}=frac{y+1}{5+1}=frac{z-2}{4-2} `

`=frac{x-4}{-14}=frac{y-1}{6}=frac{z-2}{2}`

Equation of plane passing through `(-10,5,4)` is


`A(x+10)+B(y-5)+C(z-4)=0`
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