If he line drawn from the point `(-2,-1,-3)` meets a plane at right angle at the point `(1,-3,3),` find the equation of the plane.

Explanation

Since, the line drawn from the point `(-2,-1,-3)`
meets a plane at right angle at the point `(1,-3,3) `


So, the plane passes through the point `(1,-3,3)`
and normal to plane is `(−3i+2j−6k)`

`⇒a=i−3j+3k`

and `N=−3i+2j−6k`

So, the equation of required plane is `(r-a).N=0`

`=>[(xi+yj+zk)−(i−3j+3k)].(−3i+2j−6k)=0`

`=>[(x−1)i+(y+3)j+(z−3)k)].(−3i+2j−6k)=0`

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