" 2."|x+(1)/(3)|>(8)/(3)

(1)/(x+2)<(8)/(x-3)

{(x){(1-sin^(2)x)/(3cos^(2)x),x (pi)/(2) then f(x) is continuous at x=(pi)/(2), if (a)a=(1)/(3),b=2 (b) a=(1)/(3),=(8)/(3)(c)a=(2)/(3),b=(8)/(3)(d) none of these

If (x^(2)-1)/(x)=(8)/(3) and x>1; find x^(3)-(1)/(x^(3))

((1)/(2)x^((1)/(3))+x^(-(1)/(3)))^(8)

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

Foctorise : (1)/(3) x^(2) - (8)/(x)

Solve (x+1)/(2x+3)=(3)/(8)

if x+(1)/(4x)=(3)/(2) find the value of 8x^(3)+(1)/(8x^(3))

[int((x+x^(3))^(1/3))/(x^(4))dx" is equal to "],[[" (1) "(3)/(8)((1)/(x^(2))-1)^(4/3)+c," (2) "-(3)/(8)[(1+(1)/(x^(2)))^(4/3)]+c],[" (3) "(1)/(8)(1+(1)/(x^(2)))^(4/3)+c," (4) "(1)/(8)((1)/(x^(2))-1)^(4/3)+c]]