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If the lines (x+4)/3=(y+6)/5=(z-1)/(-2) ...

If the lines `(x+4)/3=(y+6)/5=(z-1)/(-2)` and `3x-2y+z+5=0=2x+3y+4z-k` are coplanar, then `k=` (a)`-4` (2)` 3` (3)` 2` (4) ` 4` (5)` 1`

Text Solution

Verified by Experts

Since the lines are coplanar the value of x from 1st equation
should satisfy other equation thus having value of `k=-4`
So,
A is correct
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