Find the coordinates of the point where the line `(x-2)/3=(y+1)/4=(z-2)/2` intersect the plane `x-y+z-5=0.` Also, find the angel between the line and the plane.

Explanation

Let `(x-2)/3=(y+1)/4=(z-2)/2=a
`


`x=3a+2` and `y=4a-1` and `z=2a+2`

So,


`x-y+z-5=0`

`=>3a+2-4a-1+2a+2=5`

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