cos^(-1)((6x)/(1+9x^(2)))=-(pi)/(2)+2tan^(-1)3x th enx in

If cos^(-1)(6x)/(1+9x^(2))=-(pi)/(2)+tan^(-1)3x, then find the value of x.

If cos^(-1)((6x)/(1+9x^2))=-pi/2+2tan^(-1)3x , then find the value of x

If cos^(-1).(6x)/(1 + 9x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x , then find the values of x

If cos^(-1).(6x)/(1 + 9x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x , then find the values of x

If cos^(-1).(6x)/(1 + 9x^(2)) = -(pi)/(2) + 2 tan^(-1) 3x , then find the values of x

If cos^(-1)((6x)/(1+9x^2))=-pi/2+2tan^(-1)3x , then find the value of xdot

If cos^(-1)(6x)/(1+9x^2)=-pi/2+tan^(-1)3x , then find the value of xdot

Given that , tan^(-1) ((2x)/(1-x^(2))) = {{:(2 tan^(-1) x"," |x| le 1),(-pi +2 tan^(-1)x","x gt 1),(pi+2 tan^(-1)x"," x lt -1):} sin^(-1)((2x)/(1+x^(2))) ={{:(2 tan^(-1)x","|x|le1),(pi -2 tan^(-1)x","x gt 1 and ),(-(pi+2tan^(-1))","x lt -1):} sin^(-1) x + cos^(-1) x = pi//2 " for " - 1 le x le 1 If cos^(-1). (6x)/(1 + 9x^(2)) = - pi/2 + 2 tan^(-1) 3x" , then " x in

If "sin"^(-1)((6x)/(1+9x^2))=2 "tan"^(-1)(ax) , then a=