" Soloe for "x" : "(1)/(x)-(1)/((x-2))=3,x!=0,2

Solve for x : |(2+x,3,1),(3,1+x,2),(1,2,3+x)|=0

If x^(2)+x+1=0 then the absolute value of (x+(1)/(x))+(x^(2)+(1)/(x^(2)))+(x^(3)+(1)/(x^(3)))+...(x^(52)+(1)/(x^(52))) equals to

If x^(4) - 3x^(2) - 1 = 0 , then the value of (x^(6)-3x^(2)+(3)/(x^(2))-(1)/(x^(6))+1) is :

If x^(2)+3x+1=0 then find x^(3)+(1)/(x^(3)),x^(4)+(1)/(x^(4)),x^(2)-(1)/(x^(2)),x^(2)+(1)/(x^(2))

The value of lim _(x to 0) ( x ^(3) sin ((1)/(x)) - 2 x ^(2))/( 1 + 3x ^(2)) is

If a,B and y are the roots of x^(3)+2x+1=0 then roots of equation (x+1)^(3)+2(x^(2)-1)(x-1)-(x-1)^(3)=0 are

lim_(x->0) (x^2-3x+1)/(x-1)