Home
Class 9
MATHS
[" 31.ABCDE is a regular pentagon and bi...

[" 31.ABCDE is a regular pentagon and bisector of "/_A" meets the side "CD" at point M.Prove "],[" that "/_AMC=90^(@).]

Promotional Banner

Similar Questions

Explore conceptually related problems

ABCDE is a regular pentagon.The bisector of /_A of the pentagon meets the side CD in M* Show that /_AMC=90^(@).

ABCDE is a regular pentagon. The bisector of angle A meets the side CD at M. Find angle AMC

ABCDE is a regular pentagon.The bisector of angle A meets side CD at P, then prove that APC=90^(@).

ABCDE is a regular pentagon and bisector of BAE meets CD at M, bisector of BCD meets AM at P. Prove that CPM=36^(@).

A B C D E is a regular pentagon. The bisector of /_A of the pentagon meets the side C D in Mdot Show that /_A M C=90^0dot

ABCDE is a regular pentagon. The bisector of angle A of the pentagon meet the side CD in point M. Show that angleAMC=90^@ .

ABCDE is a regular pentagon and bisector of /_BAE meets CD at M. If bisector of /_BCD meets AM at P, find /_CPM.

A B C D E is a regular pentagon and bisector of /_B A E\ meets C D\ at Mdot If bisector of /_B C D meets A M at P , find /_C P Mdot

In an isosceles right-angled triangle ABC, /_B=90^(@) . The bisector of /_BAC intersects the side BC at the point D. Prove that CD^(2) =2BD^(2)

ABCDE is a regular pentagon. Angle bisector of angle BAE meets CD at m. angle bisector of angle BCD meets AM at P. Find the angle CPM = ?