[" If "x in{1,2,3,.....,9}" and "f_(n)(x)=xxx.x" (n "],[" digits),then "f_(n)^(2)(3)+f_(n)(2)]

If x in {1,2,3,...,9} and f_n (x) = x x x....x (n digits) , then f_n^2 (3)+f_n (2)

If x in{1,2,3......9} and f_n(x) =x x x ...x (n digits ), then f_n^2(3)+f_n(2) is equal to

Let f :R -{(3)/(2)}to R, f (x) = (3x+5)/(2x-3).Let f _(1) (x)=f (x), f_(n) (x)=f (f _(n-1) (x))) for pige 2, n in N, then f _(2008) (x)+ f _(2009) (x)=

Let f :R -{(3)/(2)}to R, f (x) = (3x+5)/(2x-3).Let f _(1) (x)=f (x), f_(n) (x)=f (f _(n-1) (x))) for pige 2, n in N, then f _(2008) (x)+ f _(2009) (x)=

f_(n)(x)=e^(f_(n-1)(x))" for all "n in N and f_(0)(x)=x," then "(d)/(dx){f_(n)(x)} is

f_(n)(x)=e^(f_(n-1)(x))" for all "n in N and f_(0)(x)=x," then "(d)/(dx){f_(n)(x)} is

f_(n)(x)=e^(f_(n-1)(x))" for all "n in N and f_(0)(x)=x," then "(d)/(dx){f_(n)(x)} is

f_(n)(x)=e^(f_(n-1)(x))" for all "n in N and f_(0)(x)=x," then "(d)/(dx){f_(n)(x)} is

f_(n)(x)=e^(f_(n-1)(x))" for all "n in N and f_(0)(x)=x," then "(d)/(dx){f_(n)(x)} is

If alpha,beta are the roots of equation , x^(2)-3x+1=0 and , f(n)=alpha^(n)+beta^(n),n in I ,then , f(n+2)=k.f(n)-f(n-2) , where k is , (A) 8 (B) 9 (C) 7 (D) 6