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Vectors drawn the origin `O` to the points `A , Ba n d C` are respectively ` vec a , vec ba n d vec4a- vec3bdot` find ` vec A Ca n d vec B Cdot`

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Given,
`OA=a,OB=b` and `OC=4a−3b`
So, `AC=OC−OA=(4a−3b)−(a) =3a−3b`
and
`BC=OC−OB(4a−3b)−(b)=4a−4b`
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