[(0)(x)/(6)*(2)/(15)=4],[(x)/(3)-(y)/(12)=(19)/(4)=0=]

Solve (x)/(6)+(y)/(15)=4 , (x)/(3)-(y)/(12)=(19)/(4)

{:((x)/(3) + (y)/(15) = 4),((x)/(3) - (y)/(12) = (19)/(4)):}

Let (x,y,z) be an arbitrary point lying on a plane P which passes through the points (42,0,0), (0,42,0) and (0,0,42), then the value of the expression 3+(x-11)/((y-19)^(2)(z-12)^(2))+(y-19)/((x-11)^(2)(z-12)^(2))+(z-12)/((x-11)^(2)(y-19)^(2))-(x+y+z)/(14(x-11)(y-19)(z-12)) is equal to :

The locus of a point "P" ,if the join of the points (2,3) and (-1,5) subtends right angle at "P" is x^(2)+y^(2)-x-8y+13=0 x^(2)-y^(2)-x+8y+3=0 x^(2)+y^(2)-4x-4y=0,(x,y)!=(0,4)&(4,0) x^(2)+y^(2)-x-8y+13=0,(x,y)!=(2,3)&(-1,5)

x,y,z be a point on plane passing through (42,0,0),(0,42,0),(0,0,42) then value of (x-11)/((y-19)^2* (z-12)^2 )+(y-19)/((x-11)^2* (z-12)^2) +(z-12)/((x-11)^2* (y-19)^2)+3 -(x+y+z)/(14(x-11)* (z-12)*(y-19) )

If x/6+y/15=4 and x/3-y/12=4 3/4 find x and y.

If A_(1),A_(2),A_(3) be the areas of circles x^(2)+y^(2)+4x+6y-19=0, x^(2)+y^(2)=9, x^(2)+y^(2)-4x-6y-12=0 respectively then

If A_(1),A_(2),A_(3) be the areas of circles x^(2)+y^(2)+4x+6y-19=0, x^(2)+y^(2)=9, x^(2)+y^(2)-4x-6y-12=0 respectively then