Find a vector of magnitude 11 in the direction opposite to that of `vec PQ`, where P and Q are the points (1,3,2) and (1,0,8) respectively.

Explanation

The vector with initial point `P(1,3,2)`
and terminal point `Q(−1,0,8)` is given by


`PQ​=(−1−1)i+(0−3)j​+(8−2)k=−2i−3j​+6k`


Thus, `QP​=−PQ​=2i+3j​−6k`


`⇒∣QP​∣=sqrt(2^2+3^2+(−6)^2)
`​

...