Prove that the lines `(x+1)/3=(y+3)/5=(z+5)/7a n d(x-2)/1=(y-4)/4=(z-6)/7` are coplanar . Also, find the plane containing these two lines.

Explanation

To prove that the lines \(\frac{x+1}{3} = \frac{y+3}{5} = \frac{z+5}{7}\) and \(\frac{x-2}{1} = \frac{y-4}{4} = \frac{z-6}{7}\) are coplanar, we can follow these steps:

### Step 1: Identify the direction ratios and points of the lines
The first line can be expressed in parametric form:
- Direction ratios: \( (3, 5, 7) \)
- Point on the line: \( (-1, -3, -5) \)

The second line can be expressed in parametric form:
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