Find the distance of the point `(1,-2,3)` from the plane `x-y+z=5` measured parallel to the line whose direction cosines are proportional to `2,3,-6.`

Explanation

Point is `(1,−2,3)`

Equation of plane `= x−y+z=5`

given line is `x/2​=y/3​=−z/6`
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`(x−1)/2​=(y+2)/3​=−(z−3)/6​=λ`

`x=2λ+1,y=3λ−2,z=−6λ+3`

Since,
`x−y+z=5`

`=>2λ+1−3λ+2−6λ+3=5`

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