Find the equation of the plane passing through the point `(0,7,-7)` and containing the line `(x+1)/(-3)=(y-3)/2=(z+2)/1` .

Explanation

The equation of the plane
containing line `(x+1)/
(−3)=(y−3)/2=(z+2)/1`
is
`a(x+1)+b(y−3)+c(z+2)=0 ---(i)`

where `−3a+2b+c=0--- (ii)`

This passes through `(0, 7, -7)`.
Thus,
`a+4b−5c=0 (iii)`

From (i) and (ii), `

a/(−14)=b/(−14)=c/(−14) `
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