Find the equation of the plane passing through the points `(1,-1,2)a n d(2,-2,2)` and which is perpendicular to the plane `x-2y+2z=9`

Explanation

Given that the plane passes through the points `(1,−1,2) ` and `(2,−2,2)`
and is perpendicular to the plane `6x−2y+2z=9`


Let the equation of the plane through `(1,−1,2)`
be
`a(x−1)+b(y+1)+c(z−2)=0-----(1)`


If it passes through `(2,−2,2)` then,
substitute for x,y and z we get,

`a(2−1)+b(−2+1)+c(2−2)=0`


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