Find the equation of the plane passing through the point whose coordinates are `(-1,1,1)a n d(1,-1,1)` and perpendicular to the plane `x+2y+3z=5.`

Explanation

Vector equation of a line passing through a point and parallel to a vector is
`r=a+λb`

where λ∈R

equation of point is

`A(x−1)+B(y−1)+C(z+1)=0 --------(1)`


Applying the condition of perpendicularity to the plane (1)
with the given planes
`x+2y+3z−7=0` and
`2x−3y+4z=0`


`A+2B+3C=7` and `2A−3B+4C=0`
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