The plane `lx+my+nz=p` intersects co-ordinate axes at A,B and C .If area of `Delta ABC` is `Delta` ,then

The plane ax+by+cz=1 meets the coordinate axes in A,B,C. The centroid of Delta ABC is

The equation of the plane, which cuts the coordinate axes at A,B and C such that the centroid of Delta ABC is at the point (-2,-1,-4),is

If a variable plane, at a distance of 3 units from the origin, intersects the coordinate axes at A,B anc C, then the locus of the centroid of Delta ABC is :

The plane (x)/(2)+(y)/(3)+(z)/(4)=1 cuts the co- ordinate axes in A,B,C: then the area of the Delta ABC is

If a plane meets the co-ordinate axes in A ,B , C such that the centroid of triangle ABC is (p ,q , r) then the equation of plane is

A variable plane lx+my+nz=p(wherel,m,n are direction cosines of normal) intersects the coordinate axes at points A,B and C , respectively.Show that the foot of the normal on the plane from the origin is the orthocenter of triangle ABC and hence find the coordinate of the circumcentre of triangle ABC.

Through the point P(h, k, l) a plane is drawn at right angles to OP to meet co-ordinate axes at A, B and C. If OP=p, A_xy is area of projetion of triangle(ABC) on xy-plane. A_zy is area of projection of triangle(ABC) on yz-plane, then