In `Delta ABC`, `sqrt(3)sin C=2sec A- TanA` and one of the sides has lengths 2 units then maximum area of `Delta ABC` is

In a triangle ABC , the sides a , b , c are in G.P., then the maximum value of angleB is

A rectangle is inscribed in an equilateral triangle of side length 2a units.The maximum area of this rectangle can be sqrt(3)a^(2)(b)(sqrt(3)a^(2))/(4)a^(2)(d)(sqrt(3)a^(2))/(2)

In a Delta ABC, if angle C =105^(@), angleB=45^(@) and length of side AC =2 units, then the length of th side AB is equal to

If area of ' formed by joining mid-points of the sides of Delta ABC is 2sq. Units. Then are of Delta ABC = (a)8 (b)4 (c)2 (d)1

In Delta ABC ,if a=2, B=120^(@),C=30^(@) then area of Delta ABC is

The ratio of the sides of a triangle ABC is 1:sqrt(3):2. The ratio A:B:C is

If in a Delta ABC, cos B = (sin A)/(2 sin C), then the triangle is

If ar( Delta ABC) = 16 cm^(2) then find the area of the triangle formed by joining the mid points of the sides of Delta ABC.

In a scalene triangle ABC the altitudes AD&CF are dropped from the vertices A&C to the sides BC&AB. The area of Delta ABC is known to be equal to 18, the area of triangle BDF is equal to 2 and length of segment DF is equal to 2sqrt(2). Find the radius of the circle circumscribed.