Find the equation of the plane passing through the point `(1,1,-1)a n d` perpendicular to the planes `x+2y+3z-7=0a n d2x-3y+4z=0.`

Explanation

To find the equation of the plane passing through the point \( (1, 1, -1) \) and perpendicular to the given planes, we will follow these steps:

### Step 1: Identify the Normal Vectors of the Given Planes
The equations of the given planes are:
1. \( x + 2y + 3z - 7 = 0 \)
2. \( 2x - 3y + 4z = 0 \)

From these equations, we can extract the normal vectors:
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