Find the equation of a plane which is at a distance of `3sqrt(3)` units from the origin and the normal to which is equally inclined with the coordinate axes.

Explanation

Let `α` be the angleand
`p=3sqrt3
​`

Let `n=(cosα)i+(cosα)j​+(cosα)k`


Then,
`cos2α+cos2α+cos2α=1`

`⇒3cos2α=1`

`⇒cos2α=1/3​`
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