The probability of a shooter hitting a target is `3/4`. How many minimum number of times must he/she fire so that the probability of hitting the target at least once is more than 0.99?

Explanation

To solve the problem step by step, we need to find the minimum number of times a shooter must fire so that the probability of hitting the target at least once is more than 0.99.

### Step 1: Understand the problem
The probability of hitting the target (P) is given as \( \frac{3}{4} \). The probability of missing the target (Q) is therefore \( 1 - P = 1 - \frac{3}{4} = \frac{1}{4} \).

### Step 2: Set up the probability condition
We want the probability of hitting the target at least once in N trials to be greater than 0.99. The probability of hitting the target at least once can be expressed as:
\[
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