In the circuit shown in the Figure, the voltage across resistance R, box A and box B are represented as
`v_(R)=vsin(omegat),v_(A)=sqrt(2)Vsin(omegat+(pi)/(4))and`
`v_(B)=vsin(omegat+(pi)/(2))`Find the phase difference between current and the applied voltage.

The instantaneous voltages at three terminals marked X, Y and Z are given by V_(X)=V_(0)sin omegat, V_(Y)=V_(0)sin (omegat=(2pi)/(3))and V_(z)=V_(0)sin (omegat=(4pi)/(3)) An ideal voltmeter is configured to read runs value of the potential difference between its terminals. is connected between points X and Y and then between Y and Z. The reading the voltmeter will be

The instantaneous voltages at three terminals marked X, Y and Z are given by V_(X)=V_(0)sin omegat, V_(Y)=V_(0)sin (omegat=(2pi)/(3))and V_(z)=V_(0)sin (omegat=(4pi)/(3)) An ideal voltmeter is configured to read runs value of the potential difference between its terminals. is connected between points X and Y and then between Y and Z. The reading the voltmeter will be

In the circuit shown the source voltage is given as v = V_(0) sin omegat . Find the current through the source as a function of time.

The values of current and voltage in an AC circuits are respectively I=4 sin omegat and e=100cos[omegat+(pi//3)] . The phase difference between voltage and current is

An Ac voltage V=V_0 sin 100t is applied to the circuit, the phase difference between current and voltage is found to be pi/4 , then .

An Ac voltage V=V_0 sin 100t is applied to the circuit, the phase difference between current and voltage is found to be pi/4 , then .

An Ac voltage V=V_0 sin 100t is applied to the circuit, the phase difference between current and voltage is found to be pi/4 , then .

In the LCR circuit shown in figure unknown resistance and alternating voltage source are connected.When swith S is closed then there is a phase difference of pi/4 between current and applied voltage and voltage across resister is 100/sqrt2 V .When switch is open current and applied voltage are in same phase.Neglecting resistance of connecting wire answer the following questions : Peak voltage of applied voltage sources is:

In the LCR circuit shown in figure unknown resistance and alternating voltage source are connected.When swith S is closed then there is a phase difference of pi/4 between current and applied voltage and voltage across resister is 100/sqrt2 V .When switch is open current and applied voltage are in same phase.Neglecting resistance of connecting wire answer the following questions : Peak voltage of applied voltage sources is: