" The solution of "sin^(-1)x-sin^(-1)2x=+-(pi)/(3)" is "

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

Solve sin^(-1)x+sin^(-1)2x=(pi)/(3)

The solution of sin^(-1)x - sin^(-1)2x = pm pi/3 is a) pm1/3 b) pi1/4 c) pmsqrt3/2 d) pm1/2

STATEMENT-1: The solution of sin^(-1)6x+sin^(-1)6sqrt(3)x=(pi)/(2) is x=+-(1)/(12) .and STATEMENT -2 As,sin^(-1)x is defined for |x|<=1

Solve sin^(-1)x + sin^(-1) 2x = (pi)/(3)

Solve : sin^(-1)x + sin^(-1) 2x = (pi)/(3)