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[" If "int(0)^(2)log cos xdx=(pi)/(2)log...

[" If "int_(0)^(2)log cos xdx=(pi)/(2)log((1)/(2))," then "int_(0)^((pi)/(2))log sec xdx=],[[" MHT CET "2017]]

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If int_(0)^((pi)/(2))logcosxdx=(pi)/(2)log((1)/(2)) , then int_(0)^((pi)/(2))logsecdx=

If int_(0)^(pi//2) log cos x dx =(pi)/(2)log ((1)/(2)), then int_(0)^(pi//2) log sec x dx =

If int_(0)^(pi//2) log cos x dx =(pi)/(2)log ((1)/(2)), then int_(0)^(pi//2) log sec x dx =

int_(0)^((pi)/(2))log(cos x)dx=

int_(0)^((pi)/(2))log(tanx)dx

int_(0)^(pi//2)log (sec x) dx=

Evaluate int_(0)^((pi)/(2))log sin xdx

If int_(0)^(pi//2) log(cosx) dx=pi/2 log (1/2), then int_(0) ^(pi//2) log (sec x ) dx =

int_(0)^((pi)/(2))cos^(2)xdx

int_(0)^((pi)/(2))log cos xdx equals